Reputation: 157
I currently have a list of URLs
http://www.website.com/dynamic/download.ashx?id=123/12/12345
http://www.website.com/dynamic/download.ashx?id=12/121/123451
http://www.website.com/dynamic/download.ashx?id=1/1233/123
I am looking to create a new list replacing the / with _ and stripping the URL. Creating a new list:
123_12_12345
12_121_123451
1_1233_123
I have removed the URL by splitting
for z in columns['location']:
print z.split('=')[1:]enter code here
stripped.append(z.split('=')[1:])
help to replace / with _ would be appreciated. cheers!
Upvotes: 3
Views: 1132
Reputation: 465
newink = a.split('=')[0] + a.split('=')[1].replace('/','_')
Then loop for each link to convert it
Upvotes: 0
Reputation: 14313
This will split about =, grab the second part and then replace / with _.
urls = ["http://www.website.com/dynamic/download.ashx?id=123/12/12345",
"http://www.website.com/dynamic/download.ashx?id=12/121/123451",
"http://www.website.com/dynamic/download.ashx?id=1/1233/123"]
for url in urls:
print(url.split("=")[1].replace("/","_"))
Upvotes: 1