CODEWITHSUNDEEP
c
Mike
Mike

Reputation: 1

instantiating functions and variable initialization at same time

Why doesn't the code below get compiled ? For sake of brevity, I would like the code to be written in this manner, which seems syntactically OK, but Linux gcc compiler complains

#include <stdio.h>
void fn(int in, char ch, char* str);
int main()
{
     fn(int i2 = 20, char ch2 = 'Z', char* str2 = "Hello");
     printf("in2 = %d, ch2 = %c, str2 = %s\n", in2, ch2, str2);
     return;
}

void fn(int in, char ch, char* str)
{
    printf("int = %d\n", in);
    printf("ch = %c\n", ch);
    printf("str = %s\n", str);
    return;
}

Upvotes: 0

Views: 163

Answers (2)

Federico klez Culloca
Federico klez Culloca

Reputation: 27129

Because in c89 (ANSI C) you can declare variables only at the beginning of a block.

int main()
{
    int i2 = 20; char ch2 = 'Z'; char* str2 = "Hello";
    fn(i2, ch2,str2);
    printf("in2 = %d, ch2 = %c, str2 = %s\n", in2, ch2, str2);
    return;
}

EDIT

In c99, even thought you can in other parts, you can't decalre variables inside of expressions (like a function call).

Upvotes: 2

Mariy
Mariy

Reputation: 5924

You should declare your variables outside the function call and everything will be OK.

Upvotes: 0

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