Reputation: 73282
I'm currently working on a proprietary shopping cart system and was having a few problems with getting products out with the correct pricing.
Basically my table structure is as follows:
Products table: (Only relevant columns are represented)
----------------------------------------------------
productid | product | descr | disporder| list_price|
----------------------------------------------------
1 name desc 1 0.00
2 name desc 4 0.00
3 name desc 2 2.45
Pricing table:
----------------------------------------
priceid | productid | price | variantid|
----------------------------------------
1 1 13.91 1
2 2 54.25 4
3 2 47.23 2
Variants Table:
-------------------------------
variantid | productid | active|
-------------------------------
1 1 Y
2 2 Y
3 2 Y
So, each product can have - and in most cases does have - multiple variants. My current SQL query I have managed to create thus far is:
SELECT
products.productid, product, descr, p.price, i.image_path
FROM
products
LEFT JOIN
pricing AS p
ON
p.variantid = (SELECT variantid FROM variants
WHERE productid = products.productid LIMIT 1)
LEFT JOIN
images_T AS i
ON
i.id = products.productid
GROUP BY
products.productid
ORDER BY
products.disporder
However, my problem arises when a product does not have a variant. If a product does not have a variant associated with it, the price will be in the list_price
column of the products
table. How would I go about performing a check to see if a product does indeed have a variant. If not, it should effectively bypass the variants
table and get the pricing from list_price
within the products
table.
Upvotes: 0
Views: 574
Reputation: 7420
Yes, CASE is an option, or COALESCE:
SELECT
products.productid, product, descr,
COALESCE(products.list_price, p.price) AS price,
i.image_path
...
Just join both prices and when the first is NULL the other will be selected.
Upvotes: 2
Reputation: 129363
You can do a full join with variants table (which will ONLY give you producs which have variants), and then UNION it with a join of producs and pricing where there exists no varian (using AND NOT EXISTS (SELECT 1 from variants WHERE p.productid=v.productid and p.variantid =v.variantid)
Otherwise, use CASE on pricing.price
Upvotes: 1
Reputation: 16708
The simplest way is to use a CASE
in the SELECT
clause, like so:
SELECT
products.productid, product, descr,
CASE
WHEN p.price IS NULL
THEN products.list_price
ELSE p.price
END AS price,
i.image_path
[...]
Since you're left-joining on pricing/variants, p.price
should reliably be NULL for products with no variants.
Hopefully that's what you meant by "bypassing" the variants table. :)
Upvotes: 2