CODEWITHSUNDEEP
c++regexstringc++11replace
Shravan40
Shravan40

Reputation: 9898

Replace a specific character with another from regex match?

I am trying to replace * with whenever \w*\w pattern is found. Here is what I have 

#include <string>
#include <iostream>
#include <regex>

using namespace std;

int main() {
    string text = "Dear Customer, You have made a Debit Card purchase of INR962.00 on 26 Oct. Info.VPS*Brown House. Your Net Available Balance is INR 5,584.58.";

    regex reg("[\w*\w]");
    text = regex_replace(text, reg, " ");
    cout << text << "\n";
}

But it replace the * with and w with also.

Output of the above program is 

Dear Customer, You have made a Debit Card purchase of INR962.00 on 26 Oct. Info.VPS Bro n House. Your Net Available Balance is INR 5,584.58.

Upvotes: 0

Views: 210

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626920

Use

regex reg(R"(([a-zA-Z])\*(?=[a-zA-Z]))");
text = regex_replace(text, reg, "$1 ");
// => Dear Customer, You have made a Debit Card purchase of INR962.00 on 26 Oct. Info.VPS Brown House. Your Net Available Balance is INR 5,584.58.

See C++ online demo

The R"(([a-zA-Z])\*(?=[a-zA-Z]))" is a raw string literal where \ is treated as a literal \ symbol, not an escaping symbol for entities like \n or \r.

The pattern ([a-zA-Z])\*(?=[a-zA-Z]) matches and captures an ASCII letter char (with ([a-zA-Z])), then matches a * (with \*) and then requires (does not consume) an ASCII letter char (with (?=[a-zA-Z])).

The $1 is the backreference to the value captured with the ([a-zA-Z]) group.

Upvotes: 2

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