CODEWITHSUNDEEP
javascriptarraysjsonobject
Elizabeth
Elizabeth

Reputation: 66

how to create a javascript object without double quotes on the property value

From this data

[{"lat":"-1.325416","lng":"36.669051"},
 {"lat":"-1.392932","l‌​ng":"36.768752"},
 {"l‌​at":"-1.390505","lng‌​":"36.810023"},
 {"lat‌​":"-1.448266","lng":‌​"36.952769"},
 {"lat":‌​"-1.267033","lng":"3‌​7.094882"},
 {"lat":"-‌​1.214605","lng":"37.‌​053978"},
 {"lat":"-1.‌​169516","lng":"36.89‌​5608"}]

I am trying to create a javascript object that looks like this. 

 var outerCoords =[
          {lat: -1.325416, lng: 36.669051},
          {lat: -1.392932, lng: 36.768752},
          {lat: -1.390505, lng: 36.810023},
          {lat: -1.448266, lng: 36.952769},
          {lat: -1.267033, lng: 37.094882},
          {lat: -1.214605, lng: 37.053978}, 
          {lat: -1.169516, lng: 36.895608},
          {lat: -1.244058, lng: 36.730391}
        ],

the property value without double quotes. I have first, stringified my json to get a string, then removed the double quotes from the string, then parsed the result with no double quotes. Parsing the result does not create an object, it returns a string. Please if you can help i'll appreciate. This is what am doing.

var str= JSON.stringify(outercords1); 
var x = str.replace (/"/g,'');
var obj= JSON.parse(x);

the value of outercords is:

[{"lat":"-1.325416","lng":"36.669051"},{"lat":"-1.392932","lng":"36.768752"},{"lat":"-1.390505","lng":"36.810023"},{"lat":"-1.448266","lng":"36.952769"},{"lat":"-1.267033","lng":"37.094882"},{"lat":"-1.214605","lng":"37.053978"},{"lat":"-1.169516","lng":"36.895608"}]

Upvotes: 3

Views: 4083

Answers (5)

Anil
Anil

Reputation: 3752

You can use JSON.parse with a custom reviver function to manipulate your elements.

var outderCoords1=[{"lat":"-1.325416","lng":"36.669051"},
 {"lat":"-1.392932","lng":"36.768752"}];

var outerCoords = JSON.parse(JSON.stringify(outderCoords1), 
   function(name, value) {
   if(!(typeof value.replace === "undefined")){
       var v= parseFloat(value.replace(/"/g, ""));
            alert(typeof(v));
           } 
        });

Upvotes: 0

Vikram Pawar
Vikram Pawar

Reputation: 138

Well I think don't use stringify that solve your problem try it as it is.

Upvotes: 1

Nina Scholz
Nina Scholz

Reputation: 386560

You could iterating the array and the objects and convert all stringed numbers to number.

The keys have, according to the JSON, always double quotes.

 var outerCoords = [{ "lat": "-1.325416", "lng": "36.669051" }, { "lat": "-1.392932", "lng": "36.768752" }, { "lat": "-1.390505", "lng": "36.810023" }, { "lat": "-1.448266", "lng": "36.952769" }, { "lat": "-1.267033", "lng": "37.094882" }, { "lat": "-1.214605", "lng": "37.053978" }, { "lat": "-1.169516", "lng": "36.895608" }];

outerCoords.forEach(function (o) {
    Object.keys(o).forEach(function (k) {
        if (isFinite(o[k])) {
            o[k] = +o[k];
        }
    });
});

console.log(outerCoords);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 0

Atanu Mallick
Atanu Mallick

Reputation: 356

var outerCoords =[
    {lat: -1.325416, lng: 36.669051},
    {lat: -1.392932, lng: 36.768752},
    {lat: -1.390505, lng: 36.810023},
    {lat: -1.448266, lng: 36.952769},
    {lat: -1.267033, lng: 37.094882},
    {lat: -1.214605, lng: 37.053978}, 
    {lat: -1.169516, lng: 36.895608},
    {lat: -1.244058, lng: 36.730391}
]
        
var str= JSON.stringify(outerCoords); 
//var x = str.replace (/"/g,'');
var obj= JSON.parse(str);
console.log(obj);

Upvotes: 0

ffflabs
ffflabs

Reputation: 17481

Stringified JSON has quoted properties. This is mandatory. So a javascript object in the form

var outerCoords =[
      {lat: -1.325416, lng: 36.669051},
      {lat: -1.392932, lng: 36.768752},
      {lat: -1.390505, lng: 36.810023},
      {lat: -1.448266, lng: 36.952769},
      {lat: -1.267033, lng: 37.094882},
      {lat: -1.214605, lng: 37.053978}, 
      {lat: -1.169516, lng: 36.895608},
      {lat: -1.244058, lng: 36.730391}
    ],

Will be stringified as

'[{"lat":-1.325416,"lng":36.669051},{"lat":-1.392932,"lng":36.768752},{"lat":-1.390505,"lng":36.810023},{"lat":-1.448266,"lng":36.952769},{"lat":-1.267033,"lng":37.094882},{"lat":-1.214605,"lng":37.053978},{"lat":-1.169516,"lng":36.895608},{"lat":-1.244058,"lng":36.730391}]'

removing the quotes will turn it invalid to be parsed as JSON, so that's why you're getting a string.

On the other hand, performing

JSON.parse('[{"lat":-1.325416,"lng":36.669051},{"lat":-1.392932,"lng":36.768752},{"lat":-1.390505,"lng":36.810023},{"lat":-1.448266,"lng":36.952769},{"lat":-1.267033,"lng":37.094882},{"lat":-1.214605,"lng":37.053978},{"lat":-1.169516,"lng":36.895608},{"lat":-1.244058,"lng":36.730391}]');

Will give you an object. The same object you hand when you begun.

Object properties are always casted as strings, so declaring your object as

var outerCoords =[
  {"lat": -1.325416, "lng": 36.669051},
  {"lat": -1.392932, "lng": 36.768752},
  {"lat": -1.390505, "lng": 36.810023},
  {"lat": -1.448266, "lng": 36.952769},
  {"lat": -1.267033, "lng": 37.094882},
  {"lat": -1.214605, "lng": 37.053978}, 
  {"lat": -1.169516, "lng": 36.895608},
  {"lat": -1.244058, "lng": 36.730391}
];

is the same as declaring it without quotes.

Upvotes: 2

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