CODEWITHSUNDEEP
c
abinjacob
abinjacob

Reputation: 23

Is there any operator in c which avoids any change in value of variable after the first assignment?

In this code once f is assigned some value of i, for example from inside the loop after 3 iterations f=i=2, then next time f cannot be assigned the value again: the value of f has to be rock solid to first assignment only.

    for(i=0;i<N-1;i++)
       {
        if(array[i+1]>array[i]);
        else if(array[i+1]<array[i])
        {
         f=i;s=i+1;}
        else
         {f=i;
         s=i+1;}
       }

Once f is initialized to one value of i it should not change. Is there any operator in C which helps? I thought of static but it's absolutely the wrong choice.

Upvotes: 0

Views: 79

Answers (2)

Neil Roy
Neil Roy

Reputation: 632

There is simply no way to do what you want in C. You cannot set a variable to any value and then prevent it from being set again in the future. The best you can do is to set it some some value you do not plan to use normally, like -1 or something, then check to see if it equals that before you set it. But you cannot prevent it from being set by some operator.

Upvotes: 1

Tim Biegeleisen
Tim Biegeleisen

Reputation: 522049

You could set f equal to some placeholder value initially. Then, check for this placeholder and only make an assignment once:

int f = -1;
for (i=0; i < N-1; i++)
{
    if (array[i+1] > array[i]);
    else if (array[i+1] < array[i])
    {
        if (f == -1) f = i;
        s = i+1;
    }
    else
    {
        if (f == -1) f = i;
        s = i+1;
    }
}

Upvotes: 3

Related Questions