Reputation: 1
I am working on choropleth using plotly in Jupyter Notebook.I want to plot choropleth but its showing me empty output.I am working with offline plotly.In html its genrated chart successfuly but when i tried offline it shows me empty output.please tell me how i solve this error. here is my code
from plotly.graph_objs import * from plotly.offline import download_plotlyjs, init_notebook_mode, iplot from plotly.offline.offline import _plot_html init_notebook_mode(connected=True) for col in state_df.columns: state_df[col] = state_df[col].astype(str) scl = [[0.0, 'rgb(242,240,247)'],[0.2, 'rgb(218,218,235)'],[0.4, 'rgb(188,189,220)'],\ [0.6, 'rgb(158,154,200)'],[0.8, 'rgb(117,107,177)'],[1.0, 'rgb(84,39,143)']] state_df['text'] = state_df['StateCode'] + '<br>' +'TotalPlans '+state_df['TotalPlans'] data = [ dict( type='choropleth', colorscale = scl, autocolorscale = False, locations = state_df['StateCode'], z = state_df['TotalPlans'].astype(float), locationmode = 'USA-states', text = state_df['text'], marker = dict( line = dict ( color = 'rgb(255,255,255)', width = 2 ) ), colorbar = dict( title = "Millions USD" ) ) ] layout = dict( title = 'Plan by States', geo = dict( scope='usa', projection=dict( type='albers usa' ), showlakes = True, lakecolor = 'rgb(255, 255, 255)', ), ) fig = dict(data=data, layout=layout) plotly.offline.iplot(fig)
Upvotes: 0
Views: 868
Reputation: 31659
You are passing a dict
ionary to iplot
which in contradiction to the documentation can handle only Figure
objects and not dictionaries.
Try
fig = Figure(data=[data], layout=layout)
and it should work.
Upvotes: 1