CODEWITHSUNDEEP
pythonlistpython-3.xdictionaryoptimization
Villiam
Villiam

Reputation: 59

How to find if any element of the list is present in a dictionary

I have the following code:

fileTypes = ["photo", "audio"]
arg = {"photo": "123"}
is_file = True if [True for f in fileTypes if f in arg.keys()] else False

The is_file output is True, if "photo" or "audio" is one of the keys of arg.

I want is_file to return False or one of file type, if it is set in arg. One of the file types can be in the arg dict.

Also, I think this is not optimized. I'd like a better alternative.

Upvotes: 2

Views: 54

Answers (1)

Ivan Chaer
Ivan Chaer

Reputation: 7100

What about any()?

from timeit import timeit

def list_comprehension_method():

    fileTypes = ["photo", "audio"]
    arg = {"photo": "123"}
    return True if [True for f in fileTypes if f in arg.keys()] else False

def any_method():

    fileTypes = ["photo", "audio"]
    arg = {"photo": "123"}
    return any(f in arg.keys() for f in fileTypes)


number = 1000

print('any_method:                 ', timeit('f()', 'from __main__ import any_method as f', number=number))
print('list_comprehension_method:  ', timeit('f()', 'from __main__ import list_comprehension_method as f', number=number))

Python 2.7:

any_method:                 0.001070976257324218
list_comprehension_method:  0.001577138900756836

Python 3.6:

any_method:                  0.0013788840005872771
list_comprehension_method:   0.0015097739960765466

Upvotes: 2

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