Reputation: 11
I have a database column the holds timestamps in UNIX format, I am looking for a way to compare those timestamps to a timestamp from the time right now and print how many seconds/hours/days since the original timestamp.
Just to confirm I am NOT looking for a conversion from 1489757456
to 03/17/2017 @ 1:30pm
. I AM looking for a conversion from 1489757456
to 1m ago/2hr ago/3d ago
ect.
Upvotes: 1
Views: 393
Reputation: 9993
Function, like this will generate output for hours, mins and seconds from seconds number.
def secondsToHms(d):
d = int(d);
h = math.floor(d / 3600)
m = math.floor(d % 3600 / 60)
s = math.floor(d % 3600 % 60)
htext = " hour, " if h == 1 else " hours, "
hDisplay = str(h) + htext if h > 0 else ""
mtext = " minute, " if m == 1 else " minutes, "
mDisplay = str(m) + mtext if m > 0 else ""
stext = " second" if s == 1 else " seconds"
sDisplay = str(s) + stext if s > 0 else ""
return hDisplay + mDisplay + sDisplay;
For example:
secondsToHms(344334)
>> 95.0 hours, 38.0 minutes, 54.0 seconds
So you can add your preferred formatting and also add days/months if needed in similar fashion.
Upvotes: 1
Reputation: 352
datetime.datetime.fromtimestamp()
to convert your unix timestamp to a datetitme
datetime.datetime.now()
to get the current datetime
dateutil.relativedelta.relativedelta(dt1, dt2, ...)
to get the difference with respect to leap years.
References:
Upvotes: 1