Reputation: 41595
I'm trying to use an array of middlewares. Well, more like a combination of function names and arrays.
Instead of having:
router.post('/editPassword', validate, changePassword, sendConfirmation);
I would like to have something like:
router.post('/editPassword', validate, [changePassword, sendConfirmation] );
That would look like:
router.post('/editPassword', validate, doAction );
Where doAction
would be an array like this:
var doAction = [
//equivalent of changePassword
function(req, res, next){
//whatever
next();
},
//equivalent to the previous sendConfirmation
function(req, res, next){
//whatever
}
]
But it seems it is failing and going back to the validate
step after the next()
within the first function in doAction
.
I'm looking for a way to simplify the middleware chaining including some middleware steps under the same name.
Upvotes: 7
Views: 16246
Reputation: 77024
This functionality is already built into express as an array or middleware:
let combined = express.Router()
.use(
[
middleware1,
middleware2,
middleware3,
],
);
let combined = express.Router()
.use(
middleware1,
middleware2,
middleware3,
);
"use strict";
let Http = require("http");
let Express = require("express");
let server = Express();
let app = Express.Router();
let combined = Express.Router();
combined.use(
function (req, res, next) {
console.log("huzzah!");
next();
},
function (req, res, next) {
res.json({ success: true });
}
);
function middleware0(req, res, next) {
console.log('ground zero');
next();
}
app.get("/combined", middleware0, combined);
server.use("/", app);
Http.createServer(server).listen(3000);
Upvotes: 0
Reputation: 364
Latest version of Express can handle this:
function logOriginalUrl (req, res, next) {
console.log('Request URL:', req.originalUrl)
next()
}
function logMethod (req, res, next) {
console.log('Request Type:', req.method)
next()
}
var logStuff = [logOriginalUrl, logMethod]
app.get('/user/:id', logStuff, function (req, res, next) {
res.send('User Info')
})
You can review more from this link
Upvotes: 5
Reputation: 1893
I assume the reason you wanted it to look that way is not only for it to appear presentable, but also to be able to reuse the other middleware. In that case, you can create a middleware which runs all other middlewares to do the check for you, and only calls the next function if all validations succeed.
var express = require('express');
var app = express();
function middleware1(req, res, next) {
if(req.query.num >= 1) {
next();
} else {
res.json({message: "failed validation 1"});
}
}
function middleware2(req, res, next) {
if(req.query.num >= 2) {
next();
} else {
res.json({message: "failed validation 2"});
}
}
function middleware3(req, res, next) {
if(req.query.num >= 3) {
next();
} else {
res.json({message: "failed validation 3"});
}
}
function combination(req, res, next) {
middleware1(req, res, function () {
middleware2(req, res, function () {
middleware3(req, res, function () {
next();
})
})
})
}
app.get('/', combination, function (req, res) {
res.send('Passed All Validation!');
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})
You can test this app by running it then viewing http://localhost:3000/?num=3
, changing the value 3 to a lower number, or removing the num parameter.
I'm not sure if this is the proper way to do it, but this is how I've handled my other projects. Let me know what you think.
note: see comments for use case. @robertklep may have a better solution depending on how you want to use middlewares
Upvotes: 5
Reputation: 203304
Be careful that you're not doing (the equivalent of) this in your validate
middleware:
function middleware(req, res, next) {
if (someCondition) {
console.log('some condition is true');
next();
}
console.log('some condition is false');
res.status(400).end();
}
The intention here is that after calling next
the rest of the code isn't executed, but it will. There's nothing really special about next
, so when you call it, after it returns the middleware code continues to run (causing both "some condition is true" and "some condition is false" to be logged).
That's why you often see this:
if (someCondition) {
console.log('some condition is true');
return next();
// Or, alternatively:
// next();
// return;
}
The return
causes the middleware function to return after calling next
, so the rest of the code in the function won't be executed.
Upvotes: 2
Reputation: 783
Just search a little more ^^ : Less ugly and more understandable than previous answer
https://github.com/blakeembrey/compose-middleware
Upvotes: 3