CODEWITHSUNDEEP
c#
Dmitri Nesteruk
Dmitri Nesteruk

Reputation: 23789

What's happening with the 2nd element of the array?

Suppose I write

int numbers[] = {1,2,3};
ref int second = ref numbers[1];
Array.Resize(ref numbers, 1);
Console.WriteLine(second); // works fine
second = 321; // also legit

How does this work? Have I magically allocated numbers[1] as a separate, addressable number on the managed heap? What's going on here?

Upvotes: 3

Views: 71

Answers (2)

Lasse V. Karlsen
Lasse V. Karlsen

Reputation: 391276

Array.Resize creates a new array, leaving the old one on the heap, as per the documentation:

This method allocates a new array with the specified size, copies elements from the old array to the new one, and then replaces the old array with the new one.

(my emphasis)

Note: The documentation is slightly misleading depending on how you understand it. It says "then replaces the old array with the new one". What it means is that it replaces the reference you have in the array variable, numbers in your example, with a reference to the new array. The old array object is left intact and untouched in memory.

If you didn't have a ref int reference into it, GC would eventually pick it up, but since you do, it doesn't.

second = 321 changes the original array, not the new one.

You can easily show this using a very simple example:

using System;

public class Program
{
    public static void Main()
    {
        int[] a = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
        int[] b = a;
        ref int a1 = ref a[1];

        Array.Resize(ref a, 5);

        a1 = 100;
        Console.WriteLine(a[1]); // new
        Console.WriteLine(b[1]); // original
        Console.WriteLine(ReferenceEquals(a, b));
    }
}

This outputs:

2            // the new array, which did not change
100          // the original array, which did change
false        // not the same arrays

So the ref int variable did change, and the original array did change, but the new, size-modified, copy did not.

See this example on .NET fiddle

Upvotes: 9

Dmitry Savy
Dmitry Savy

Reputation: 1067

This method allocates a new array with the specified size, copies elements from the old array to the new one, and then replaces the old array with the new one.array must be a one-dimensional array.

If array is null, this method creates a new array with the specified size.

If newSize is greater than the Length of the old array, a new array is allocated and all the elements are copied from the old array to the new one. If newSize is less than the Length of the old array, a new array is allocated and elements are copied from the old array to the new one until the new one is filled; the rest of the elements in the old array are ignored. If newSize is equal to the Length of the old array, this method does nothing.

Straight from MSDN

Upvotes: 3

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