CODEWITHSUNDEEP
javascriptnode.jsexpress
user2924127
user2924127

Reputation: 6242

Nodejs - load module once and use in many different files

My project directory looks something like this:

MyProject
    -app.js
    -routes
        -routeone
        -routetwo

Inside of my app.js file it looks like this:

var express = require('express');
var app = express();
var myModule= require('myModule');
app.use(myModule());

var routeone = require('./routes/routeone');
var routetwo = require('./routes/routetwo');

app.use('/routeone', routeone);
app.use('/routetwo', routetwo);
.
.
.

Each route file looks something like this:

var express = require('express');
var router = express.Router();


router.post('/', urlencodedParser, function(req, res, next) {
    //Need to call myModule's createUser function. How do I call it here?
});
module.exports = router;

As you can see I have a dependency on the myModule module. I need to call a function in this module in every route.I may have many more routes in the future. I would like to avoid specifying this (calling require) in every single route file because in the future if I have hundreds of route and say the module now accepts options I would need to to every single file and since this manually. Is there a way to require it once (e.g in the app.js file) and then be able to use it everywhere?

Upvotes: 1

Views: 428

Answers (1)

Sikorski
Sikorski

Reputation: 2691

You can write your route modules as such that during the time of creation(require call) they get their dependencies injected. I have added a sample below

route.js

module.exports = function(myModule, router, dep1, dep2){
router.post()
//use my module, dep1 and dep2

}

app.js

var mymodule = require('./myModule')
var dep1 = require('./dep1');
var dep2 = require('./dep2');
var router = express.Router();
var route = require('route')(mymodule, router, dep1, dep2);

Update - For returning router instance from route.js

route.js

module.exports = function(myModule, dep1, dep2){
router.post()
//other router invocations
return router
}

In app.js

var customRouter = require('route')(mymodule, router, dep1, dep2);

the customRouter will be an router instance since thats what is being returned by te invoked function in route.js

Upvotes: 2

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