CODEWITHSUNDEEP
pythonpython-3.xloops
hypersonicelf
hypersonicelf

Reputation: 1

Using for loops over while loops

How would one produce some code that counts up using a for loop as opposed to a while loop? My code is as follows;

def square():
    count = 1
    number = input("How far?")
    number = int(number)
    if number < 1:
        print ("broken")
    elif number >= 1:
        while count <= number:
            square = count*count
            print ("{0}*{0}={1}".format(count, square))
            count = count+1
square()

Upvotes: 0

Views: 81

Answers (2)

Bohdan Biloshytskiy
Bohdan Biloshytskiy

Reputation: 405

U can do it with list comprehensions like:

def square():
    number = int(input("How far?"))
    # range will be from 1 to number +1, and will proceed square for all
    return [val ** 2 for val in range (1, number+1)]

squares = square()
if not squares:
    print('broken')
# u can iterate over result even if list is empty(if u pass broken number)
for val in squares:
    print ("{0}*{0}={1}".format(count, square))

Upvotes: 0

Miriam Farber
Miriam Farber

Reputation: 19634

You can do it like that:

def square():
    number = input("How far?")
    number = int(number)
    if number < 1:
        print ("broken")
    elif number >= 1:
        for count in range(1,number+1):
            square = count*count
            print ("{0}*{0}={1}".format(count, square))
square()

Using the line 

for count in range(1,number+1):

counts iterates over the values 1,2,...,number.

Upvotes: 1

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