Reputation: 1133
MY CODE
function validate(e, id) {
var reg = new RegExp('^\\d+$');
if (reg.test($("#" + id).val())) {
var value = $("#" + id).val();
alert(value);
} else {
alert("fail");
}
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<input name="input-type" type="number" id="number-input" oninput="validate(event,'number-input');">
This accept 1.(dot after any digits) value rest all is good.
Upvotes: 1
Views: 1265
Reputation: 3541
Here is a code that might help you.In the below code when the user types .
it is replaced by null
.It only accepts digits.This is for input type="text"
.The variable currValue
has the value of the input.
The search() method searches a string for a specified value, and returns the position of the match.The search value can be string or a regular expression.This method returns -1 if no match is found.
Then I am using .replace()
The replace() method searches a string for a specified value, or a regular expression, and returns a new string where the specified values are replaced.
Here I am replacing it with null if the regex doesn't match.The regex [^0-9]
checks if not digit.
Here is the code:
$(function() {
$('input').bind('keyup', function(event) {
var currValue = $(this).val();
if (currValue.search(/[^0-9]/) != -1) {
alert('Only numerical inputs please');
}
$(this).val(currValue.replace(/[^0-9]/, ''));
alert($(this).val());
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<label>Digits Only:
<input type="text" />
</label>
<br>
<br>
EDIT :
In input type="number"
we have to force it to always accept the updated val
since many events does not work in it.So for that reason I have to update the existing value with the updated value after each event.
So I added
var v = $(this).val();
$(this).focus().val("").val(v);
So that each time the input is focused the value get updated with the existing value.
UPDATED FIDDLE FOR INPUT TYPE NUMBER
Updated snippet:
$(function() {
$('input').bind('keyup input', function(event) {
var v = $(this).val();
$(this).focus().val("").val(v);
var currValue = $(this).val();
if (currValue.search(/[^0-9]/) != -1) {
alert('Only numerical inputs please');
}
$(this).val(currValue.replace(/[^0-9]/, ''));
alert($(this).val());
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label>Digits Only:
<input type="number" />
</label>
<br>
<br>
EDIT 2 : For special case +
and -
.I think its a bug I am not sure but check the below snippet.It works for all the cases.Hope it helps.
$(function() {
$('input').bind('keyup', function(event) {
var v = $(this).val();
$(this).focus().val("").val(v);
var currValue = $(this).val();
$(this).val(currValue.replace(/[^0-9]/, ''));
alert(v);
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label>Digits Only:
<input type="number" name="test" min=0 save="" oninput="validity.valid ? this.save = value : value = this.save;">
</label>
<br>
<br>
Hope it helps.For any other doubt feel free to ask.
Upvotes: 0
Reputation: 32231
It work as fallow:
1 pass
1. fail
1.1 pass
function validate(e, id) {
var value = $("#" + id).val() + "";
if (new RegExp('^[0-9]+\.[0-9]+$').test(value)
|| ((new RegExp('^[0-9]+').test(value) && !value.includes(".")))
) {
var value = $("#" + id).val();
alert($("#" + id).val() + "->" + value);
} else {
alert("fail " + $("#" + id).val());
}
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<input name="input-type" type="text" id="text-input" oninput="validate(event,'text-input');">
Upvotes: 0
Reputation: 24925
You can try using <input type="tel" ...>
. This way when user types 1.
you will receive 1.
only and not 1
and it will also open number keypad on mobile.
function validate(e, id) {
var reg = /^[0-9]*(\.(?=[0-9]+))*[0-9]+$/;
var value = $("#" + id).val();
if (reg.test(value)) {
console.log(value);
} else {
console.log("fail");
}
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<input name="input-type" type="tel" id="number-input" oninput="validate(event,'number-input');">
You can also refer to How to get the raw value an <input type="number"> field? for more information in why 1.
returns 1
and not 1.
Upvotes: 1