CODEWITHSUNDEEP
javaregex
pobro123
pobro123

Reputation: 183

Java RegEx string within quotes but with additional requirement

Hello this is my problem, and I would appreciate if you could help.

This is my regex: \"(.*?)\" and my goal is to collect each word etc. within "".

If i check it against {$= "a=" "a" 0 @paramGet ", b=" "b" 0 @paramGet ", rezultat=" "a" 0 @paramGet "b" 0 @paramGet + $} and collect all groups I get: 

a=  a  , b=  b  ,rezultat=  a   b

but if check it against {$= "a=" "a" 0 @paramGet ", b\"=" "b" 0 @paramGet ", rezu\"ltat=" "a" 0 @paramGet "b" 0 @paramGet + $} I get:

"a="    "a"    ", b\"    " "     " 0 @paramGet "     "ltat="    "a"   "b"

This is my question: Is there any way to make regex recognize 

a=  a  , b\"=  b  ,rezu\"ltat=  a   b

as whole?

Upvotes: 0

Views: 39

Answers (1)

M A
M A

Reputation: 72884

There are two ways to do it:

  1. You can check that the character preceding the opening and closing double quotes is not a backslash:

    [^\\]\"(.*?[^\\])\"

  2. Use a negative lookbehind regex:

    (?<!\\)\"(.*?)(?<!\\)\"

    where (?<!b)a means a not preceded with a b.

The latter seems to work better because it also matches empty strings as well.

Upvotes: 2

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