CODEWITHSUNDEEP
c++windowsstringpath
Idov
Idov

Reputation: 5124

Passing on a char* which contains a path


I'm trying to pass through several functions a string with a path but the every '\\' I put in the path becomes a single '\' in the inner function and I can't use it this way.
Is there a way to preserve the "\\" when entering a new function?
I'm using C++ on windows.
thanks :)

Upvotes: 4

Views: 977

Answers (2)

hillel
hillel

Reputation: 2373

In C++0x you will have a raw string literal:

R"(anything can appear here, even " or \\ )"

Where everything between "( and )" is part of the string -- no escaping necessary. In the current standard you can't achieve what you want.

Upvotes: 2

icecrime
icecrime

Reputation: 76745

Be prepared for some obfuscated answer.

The \ is the escape character (you have probably already encountered the \n escape sequence for example), and \\ is the escape sequence that represents a single \ character (in a sense, it can be understood as an escape of the escape character). If you really want to have \\ in your string, you'll have to use \\\\ :

std::cout << "\\\\something\\" << std::endl; /* prints "\\something\" */

Just to provide another example, suppose you'd like to have some " in a string. Writing :

const char *str = "Hello "World"";

will obviously not compile, and you will have to escape the " with a \ :

const char *str = "Hello \"World\"";

Upvotes: 13

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