Reputation: 85
I have a 10 digit phone number held in a string "3133133313" that is downloaded from CloudKit.
I'm looking to use this number to place a call. Therefore, I have the code suggested by Apple.
let call = detail.value(forKey: "Phone") as? String
let url = URL(string: call!)!
UIApplication.shared.open(url, options: [:], completionHandler: nil)
Unfortunately, this code does not work. What am I missing here that is probably blatantly obvious.
Upvotes: 0
Views: 8027
Reputation: 85
Thanks to Leo Dabus,
I simply had to add the "tel://" aspect to each phone number. In this project, I decided to add this code snippet into my function rather than my CloudKit records.
if let call = detail.value(forKey: "Phone") as? String,
let url = URL(string: "tel://\(call)"),
UIApplication.shared.canOpenURL(url) {
UIApplication.shared.open(url)
}
Upvotes: 7