CODEWITHSUNDEEP
c#operator-overloading
joshcomley
joshcomley

Reputation: 28818

What circumstance is this operator overload dealing with in C#?

Take this class and operator overload:

public class Test
{
    public static Test operator +(Test test)
    {
        return test;
    }
}

Ignoring the implementation simply returning "test" for now, in what circumstance would this operator overload be called? It is valid and compiles, but I cannot work out what it's for!

It only takes one parameter, so what it is adding?

Upvotes: 0

Views: 38

Answers (1)

Mong Zhu
Mong Zhu

Reputation: 23732

so what it is adding?

I think it does not add anything but determines a polarity in a sense. I guess it would be comparable to a sign saying negative and positive like in

int i = +5;

This compiles just fine:

Test t1 = new Test();    
Test t2 = +t1;

but this doesn't:

Test t4 = -t1;

It compiles after the addition of

public static Test operator -(Test test) { return test; }

Here is what MSDN has to say to the unary + operator

The result of the unary plus operator (+) is the value of its operand

The unary negation operator (–) produces the negative of its operand

Upvotes: 3

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