CODEWITHSUNDEEP
pythoncountpunctuation
user7742265
user7742265

Reputation:

Counting no of words including punctuation

I am trying to count the number of words in a string including the punctuation (,/;/./!/?).

So far have been able to to count only the number of words but the punctuation are not getting counted. Tried giving a space before each punctuation using replace but it still is not getting counted. Can someone help me out?

My code:

    import re
    input_text = input("Enter the data: ")
    final_text = input_text.replace(',',' ,').replace(';',' ;').replace('.',' .').replace('?',' ?').replace('!',' !')     
    count = len(re.findall(r'\w+', final_text))
    print(count)

e.g. for this input

hi. how are you? I am good! what about you? bye!

It should be 16 including all punctuation. But I am getting only 11.

Upvotes: 1

Views: 1583

Answers (2)

RomanPerekhrest
RomanPerekhrest

Reputation: 92854

Use the following approach:

s = "hi. how are you? I am good! what about you? bye!"
result = len(re.findall(r'[^\w\s]|\w+', s))

print(result)   # 16

\w+ - will match alphanumeric sequences(including underscore _)

[^\w\s] - will match all characters except alphanumeric and whitespaces

Upvotes: 2

Ashish
Ashish

Reputation: 4330

a simple solution to your problem without any imports:

my_string = "hi. how are you? I am good! what about you? bye!"
space_words = my_string.strip().split(" ")
count = len(space_words)
for word in space_words:
    for character in word:
        if not character.isalpha():
            count += 1
print count

Output:

16

Upvotes: 0

Related Questions