CODEWITHSUNDEEP
javascriptjqueryunderscore.js
Christian-G
Christian-G

Reputation: 2361

underscore filter array of nested objects

I have the following array of objects:

[{key: "test", values: [{key: "2015-05", values: [{1:2}, {3:4}]}, {}], ...]

I want to filter by the key value to only be left with values after a certain date.

I currently have this, but the resulting the structure is wrong

_.map(temp1, function(value, key) { return _.filter(value.values, function(v) { return v.key > "2015-05"; }); });

Upvotes: 0

Views: 1252

Answers (2)

mikeapr4
mikeapr4

Reputation: 2856

Slight improvement on Frank's answer:

var data = [
  {
    key: "1", 
    values: [
      {key: "2014-05", values: [{1:2}, {3:4}]},
      {key: "2015-05", values: [{1:2}, {3:4}]},
      {key: "2013-05", values: [{1:2}, {3:4}]}
    ]
  },
  {
    key: "2", 
    values: [
      {key: "2014-05", values: [{1:2}, {3:4}]},
      {key: "2015-05", values: [{1:2}, {3:4}]},
      {key: "2013-05", values: [{1:2}, {3:4}]}
    ]
  }
];

var a = _.map(data, (d) => {
  d.values = _.filter(d.values, (v) => v.key > "2014");
  return d;
});
console.log(a);
<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>

No need to parse this date format, a string comparison will suffice. Important to note, despite the _.map operation, this will modify the original.

Upvotes: 1

FrankCamara
FrankCamara

Reputation: 348

Something like this maybe?

var data = [
  {
    key: "1", 
    values: [
      {key: "2014-05", values: [{1:2}, {3:4}]},
      {key: "2015-05", values: [{1:2}, {3:4}]},
      {key: "2013-05", values: [{1:2}, {3:4}]}
    ]
  },
  {
    key: "2", 
    values: [
      {key: "2014-05", values: [{1:2}, {3:4}]},
      {key: "2015-05", values: [{1:2}, {3:4}]},
      {key: "2013-05", values: [{1:2}, {3:4}]}
    ]
  }
];

var a = _.map(data, (d) => {
  d.values = _.filter(d.values, (v) => {
    return Date.parse(v.key) > Date.parse("2014");
  });
  return d;
});

Upvotes: 0

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