Need help in JavaScript , openWindow ();

Question

I am trying to run the following JavaScript program,

function myFunction() {
  var x;
  if (confirm("Press a button!") == true) {
    x = "You pressed Ok!";
  } else {
    x = "You pressed Cancel!";
  }
  document.getElementById("demo").innerHTML = x;
}

<p>Click the button to display a confirm box.</p>
<button onclick="myFunction()">Try it</button>
<p id="demo"></p>

But I really need is not just saying "You pressed Ok" instead of that it need to open a link. Help me please.

I hope

openWindow("http://fb.com")

this line will help, but don't know where to place it and make a working program.

Answer 1

function myFunction() {
var x;
if (confirm("Press a button!") == true) {


location.href = "http://www.google.com";

} else {

x = "You pressed Cancel!";

}
document.getElementById("demo").innerHTML = x;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p>Click the button to display a confirm box.</p>

<button onclick="myFunction()">Try it</button>

<p id="demo"></p>

Answer 2

You just need to change your function and place your openWindow() call inside it. Because I don't know what your openWindow() function does, I would use window.open():

function myFunction() {
  window.open("http://fb.com");
}

Answer 3

if (confirm("Press a button!")) {
    window.open('www.google.com')
}