CODEWITHSUNDEEP
regex
Steven
Steven

Reputation: 867

Regex : Everything in group except white space

I have this regex right here :

^(@include rem\(\s*(.*)),\s*(.*)\)

That matches this string :

@include rem( padding-top, $alert-padding );

I want to be able that the group with $alert-padding ignores the white space at the end. I tried doing : 

^(@include rem\(\s*(.*)),\s*(/S)\)

replace the .* by /S but it doesn't match.

You can play around with the regex here : https://regex101.com/r/9rouVU/1/

Upvotes: 1

Views: 1987

Answers (2)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626903

You may use \S+ to match 1 or more non-whitespace characters:

^(@include rem\(\s*(\S+))\s*,\s*(\S+)\s*\)

See the regex dem0

Details:

  • ^ - start of string
  • (@include rem\(\s*(\S+)) - Group 1 capturing:
    • @include rem\( - a literal substring @include rem(
    • \s* - 0+ whitespaces
    • (\S+) - Group 2 capturing 1+ non-whitespace symbols
  • \s*,\s* - 0+ whitespaces, , and again 0+ whitespaces
  • (\S+) - 1+ non-whitespace symbols
  • \s* - 0+ whitespaces
  • \) - a literal ).

Upvotes: 3

Harald Gliebe
Harald Gliebe

Reputation: 7564

You can make the match in the second group lazy and then match for further optional whitespace:

^(@include rem\(\s*(.*)),\s*(.*?)\s*\)

Upvotes: 0

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