Reputation: 1868
I need JSON output like this,
{"restaurant":[{"id":"89","owner_id":"2161","name":"Bakso ",...}{"id":"90","owner_id":"3400","name":"Soto"}]}
And I do using this query and work perfectly:
$latest_rest = $this->Restaurants_model->getLatestRestaurants($limit)->result();
$jsonObject = array('restaurant'=>$latest_rest);
but i have query with result_array()
, because I must filtering this data through function that return result_array();
how do I convert result_array()
to result()
in CodeIgniter?
Upvotes: 0
Views: 1515
Reputation: 2875
If it is mandatory to get result in array in beginning then to get json data you can first encode data into json and later can decode as:
$object = json_decode(json_encode($array));
And, if it is not necessary in beginning then you can get result in object directly as:
$this->db->select('*')->from..........;
$query = $this->db->get();
return $query->result(); // instead of result_array();
Upvotes: 3