CODEWITHSUNDEEP
javascriptregex
Y.G.J
Y.G.J

Reputation: 1108

URL regex validation

i made that:

 /^(http[s]?://){0,1}(www.){0,1}[a-zA-Z0-9\.\-]+\.[a-zA-Z]{2,5}[\.]{0,1}

and checked it with a validator but on my page it is not working:

var re = /^(http[s]?://){0,1}(www.){0,1}[a-zA-Z0-9\.\-]+\.[a-zA-Z]{2,5}[\.]{0,1};
if (!re.test(url)) { 
    alert("url error");
    return false;
}

i get this error

Webpage error details

User Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; WOW64; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; .NET4.0C; .NET4.0E)
Timestamp: Tue, 30 Nov 2010 14:23:10 UTC


Message: Expected ')' in regular expression
Line: 781
Char: 23
Code: 0
URI: http://*************************

Upvotes: 13

Views: 51720

Answers (6)

Vin S
Vin S

Reputation: 145

var regForUrl = /(http|https):\/\/(\w+:{0,1}\w*@)?(\S+)(:[0-9]+)?(\/|\/([\w#!:.?+=&%@!\-\/]))?/;

if (!regForUrl.test(url)) {
    alert('Invalid URL-- missing "http://" or "https://"');
}

Upvotes: 0

Aamir
Aamir

Reputation: 2283

After a long research I build this reg expression. I hope it will help others too.......

   url = 'https://google.co.in';
   var re = /[a-z0-9-\.]+\.[a-z]{2,4}\/?([^\s<>\#%"\,\{\}\\|\\\^\[\]`]+)?$/;
  if (!re.test(url)) { 
     alert("url error");
   return false;
 }else{
 alert('success')
 }

Upvotes: 0

Roger
Roger

Reputation: 8586

Just in case you want to know if the url really exists:

function url_exist($url){//se passar a URL existe
    $c=curl_init();
    curl_setopt($c,CURLOPT_URL,$url);
    curl_setopt($c,CURLOPT_HEADER,1);//get the header
    curl_setopt($c,CURLOPT_NOBODY,1);//and *only* get the header
    curl_setopt($c,CURLOPT_RETURNTRANSFER,1);//get the response as a string from curl_exec(), rather than echoing it
    curl_setopt($c,CURLOPT_FRESH_CONNECT,1);//don't use a cached version of the url
    if(!curl_exec($c)){
        //echo $url.' inexists';
        return false;
    }else{
        //echo $url.' exists';
        return true;
    }
    //$httpcode=curl_getinfo($c,CURLINFO_HTTP_CODE);
    //return ($httpcode<400);
}

Upvotes: 1

Linus Kleen
Linus Kleen

Reputation: 34652

I will post, although the question has been accepted.

That regex is still incomplete.

http://www.-1-.de is not a valid domain name but would pass your test.

Here's what I use:

~^
(?:ht|f)tps?://

(?:[a-z0-9] (?:[a-z0-9-]*[a-z0-9])?      \.)*

(?:[a-z0-9][a-z0-9-]{0,62}[a-z0-9])
(?:\.[a-z]{2,5}){1,2}

$~ix

Covers http(s), ftp(s) and .co.uk TLDs and the like. Also covers subdomains which can be 1 character in length (m.example.com for mobile versions of webpages) but will not allow m-.example.com.

Surely some might object as to the regex's completeness, since .pro TLDs require at least 4 characters as a domain name. ;-)

Also IDN domain names will only pass my regex after conversion (i.e. in the "xn--" format).

Upvotes: 2

Toto
Toto

Reputation: 91528

As said Nick you have to escape \ and . unless you're using another delimitor so your regex will become :

var re = '~(https?)://)?(www\.)?[a-zA-Z0-9.-]+\.[a-zA-Z]{2,5}\.?~';

But be aware that your regex will match url like:

http://....aa.

Upvotes: 0

Nick Craver
Nick Craver

Reputation: 630597

You have to escape your special characters (/ and that . after www in this case) and att the missing trailing /, like this:

var re = /^(http[s]?:\/\/){0,1}(www\.){0,1}[a-zA-Z0-9\.\-]+\.[a-zA-Z]{2,5}[\.]{0,1}/;
if (!re.test(url)) { 
    alert("url error");
    return false;
}

Upvotes: 35

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