CODEWITHSUNDEEP
javaarraylist
hK-
hK-

Reputation: 57

Searching an ArrayList for a string and returning another associated string

private ArrayList<SocialMediaAccount> socialMediaAccounts;

public void addSocialMediaAccount(String userID, String websiteName, String websiteURL, int activityLevel) 
{
    SocialMediaAccount object = new SocialMediaAccount(userID, websiteName, websiteURL, activityLevel);
    socialMediaAccounts.add(object);
}

I have this ArrayList and I need to search for a particular websiteName and return the userID associated with the object. Getting confused a lot and would like some help on getting started with this problem. Thanks!

Upvotes: 1

Views: 160

Answers (5)

Rahul Chowdhury
Rahul Chowdhury

Reputation: 681

This should work.

//This method will return the userID associated with the given target websiteName.
//Insert it where you need it.
public String search(String targetWebsiteName){
    //loop through each account in your list.
    For(SocialMediaAccount acc: socialMediaAccounts){
      SocialMediaAccount tempObject = acc; 
       //check for websiteName
       if(tempObject.getWebsiteName().equals(targetWebsiteName)) return tempObject.getUserID();
    }
return null;
}


//Add these methods to your SocialMediaAccount class
class SocialMediaAccount{

       //Getters for object variables
       String getWebsiteName(){
            return websiteName;
       }

       String getUserID(){
           return userID;
       }
}

Upvotes: 1

Rajith Pemabandu
Rajith Pemabandu

Reputation: 616

I suppose this method will solve your question. Hope you have getters inside your socialMediaAccount class.

public String getuserID(ArrayList<SocialMediaAccount> socialMediaAccounts,String websiteName){
 for(SocialMediaAccount s:socialMediaAccounts){  
    if( s.getWebsiteName().equalsIgnoreCase( websiteName)){
        return s.getUserID;
    } 
} 
return "no user found";
}

Upvotes: 1

Kevin Anderson
Kevin Anderson

Reputation: 4592

If you have a lot of items in your list and you're doing a lot of searches, a HashMap using the the website name as the key will be much faster.

Upvotes: 1

Faraz
Faraz

Reputation: 6265

You can go through the arraylist and check if the websiteName matches the websiteName that is stored in the list like this:

for(int i = 0; i < socialMediaAccounts.size(); i++)
    if(socialMediaAccounts.get(i).getWebSiteName().equals(the_website_you_arelooking_for){
    return socialMediaAccounts.get(i).getUserId
    }
}

Upvotes: 2

Fady Saad
Fady Saad

Reputation: 1189

I think what you will want    

for (SocialMediaAccount socialMediaAccount: socialMediaAccounts) {
            if (socialMediaAccount.getwebsiteName() == your_website_search_name) {
                return socialMediaAccount.getId();
            }
        }
        return null;

Upvotes: 0

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