CODEWITHSUNDEEP
phppreg-replace
Damien
Damien

Reputation: 157

How do you replace all numbers in a string with a defined character in PHP?

How would you replace all numbers in a string with a pre-defined character?

Replace each individual number with a dash "-".

$str = "John is 28 years old and donated $40.39!";

Desired output:

"John is -- years old and donated $--.--!"

I am assuming preg_replace() will be used but I am not sure how to target just numbers.

Upvotes: 4

Views: 3835

Answers (3)

RomanPerekhrest
RomanPerekhrest

Reputation: 92854

Simple solution using strtr(to translate all digits) and str_repeat functions:

$str = "John is 28 years old and donated $40.39!";
$result = strtr($str, '0123456789', str_repeat('-', 10));

print_r($result);

The output:

John is -- years old and donated $--.--!

As alternative approach you may also use array_fill function(to create "replace_pairs"):

$str = "John is 28 years old and donated $40.39!";
$result = strtr($str, '0123456789', array_fill(0, 10, '-'));

http://php.net/manual/en/function.strtr.php

Upvotes: 5

KIKO Software
KIKO Software

Reputation: 16688

You can also do this with a normal replace:

$input   = "John is 28 years old and donated $40.39!";
$numbers = str_split('1234567890');
$output  = str_replace($numbers,'-',$input);
echo $output;

just in case you were wondering. Code was tested and it works. The output is:

John is -- years old and donated $--.--!

No need for 'obscure' regular expressions. Do you remember where the slashes and braces go and why?

Upvotes: 2

Sahil Gulati
Sahil Gulati

Reputation: 15141

PHP code demo

<?php

$str = "John is 28 years old and donated $40.39!";
echo preg_replace("/\d/", "-", $str);

OR:

<?php

$str = "John is 28 years old and donated $40.39!";
echo preg_replace("/[0-9]/", "-", $str);

Output: John is -- years old and donated $--.--!

Upvotes: 3

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