CODEWITHSUNDEEP
pythonlistiterable-unpacking
dpq
dpq

Reputation: 9268

How to unpack a list?

When extracting data from a list this way

line[0:3], line[3][:2], line[3][2:]

I receive an array and two variables after it, as should be expected:

(['a', 'b', 'c'], 'd', 'e')

I need to manipulate the list so the end result is

('a', 'b', 'c', 'd', 'e')

How? Thank you.

P.S. Yes, I know that I can write down the first element as line[0], line[1], line[2], but I think that's a pretty awkward solution.

Upvotes: 5

Views: 10734

Answers (5)

Bwmat
Bwmat

Reputation: 4578

def is_iterable(i):
    return hasattr(i,'__iter__')

def iterative_flatten(List):
    for item in List:
        if is_iterable(item):
            for sub_item in iterative_flatten(item):
                yield sub_item
        else:
            yield item

def flatten_iterable(to_flatten):
    return tuple(iterative_flatten(to_flatten))

this should work for any level of nesting

Upvotes: 0

mshsayem
mshsayem

Reputation: 18008

from itertools import chain
print tuple(chain(['a', 'b', 'c'], 'd', 'e'))

Output:

('a', 'b', 'c', 'd','e')

Upvotes: 5

Thomas K
Thomas K

Reputation: 40340

Obvious answer: Instead of your first line, do:

line[0:3] + [line[3][:2], line[3][2:]]

That works assuming that line[0:3] is a list. Otherwise, you may need to make some minor adjustments.

Upvotes: 1

kevpie
kevpie

Reputation: 26098

Try this.

line = ['a', 'b', 'c', 'de']
tuple(line[0:3] + [line[3][:1]] + [line[3][1:]])
('a', 'b', 'c', 'd', 'e')

NOTE: I think there is some funny business in your slicing logic. If [2:] returns any characters, [:2] must return 2 characters. Please provide your input line.

Upvotes: 1

slayerIQ
slayerIQ

Reputation: 1486

This function

def merge(seq):
    merged = []
    for s in seq:
        for x in s:
            merged.append(x)
    return merged

source: http://www.testingreflections.com/node/view/4930

Upvotes: 0

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