CODEWITHSUNDEEP
scalalist
Shiva Chaithanya
Shiva Chaithanya

Reputation: 54

traverse list in scala and group all the first elements and second elements

This might be pretty simple questions. I have a list named "List1" that contain list of integer pairs as below.

List1 = List((1,2), (3,4), (9,8), (9,10))

Output should be:

r1 = (1,3,9,9) //List((1,2), (3,4), (9,8), (9,10))
r2 = (2,4,8,10) //List((1,2), (3,4), (9,8), (9,10))

array r1(Array[int]) should contains set of all first integers of each pair in the list.
array r2(Array[int]) should contains set of all second integers of each pair

Upvotes: 0

Views: 150

Answers (2)

user7805515
user7805515

Reputation: 46

Just use unzip:

scala> List((1,2), (3,4), (9,8), (9,10)).unzip
res0: (List[Int], List[Int]) = (List(1, 3, 9, 9),List(2, 4, 8, 10))

Upvotes: 3

Nagarjuna Pamu
Nagarjuna Pamu

Reputation: 14825

Use foldLeft 

val (alist, blist) = list1.foldLeft((List.empty[Int], List.empty[Int])) { (r, c) => (r._1 ++ List(c._1), r._2 ++ List(c._2))}

Scala REPL

scala> val list1 = List((1, 2), (3, 4), (5, 6))
list1: List[(Int, Int)] = List((1,2), (3,4), (5,6))

scala> val (alist, blist) = list1.foldLeft((List.empty[Int], List.empty[Int])) { (r, c) => (r._1 ++ List(c._1), r._2 ++ List(c._2))}
alist: List[Int] = List(1, 3, 5)
blist: List[Int] = List(2, 4, 6)

Upvotes: 1

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