CODEWITHSUNDEEP
javajsonjackson
user1183772
user1183772

Reputation:

Avoid object with null fields using Jackson

If I try to deserialize a JSON string that is missing a field from the object class, that field is set to null when the object is created. I need Jackson to throw an exception when this happens so I don't have to implement an assertNotNullFields() method in every object; i.e the JSON string input must have defined all the fields in the class or a JsonProcessingException is thrown.

Object mapper configuration:

objectMapper.setVisibility(PropertyAccessor.ALL, JsonAutoDetect.Visibility.NONE);
objectMapper.setVisibility(PropertyAccessor.FIELD, JsonAutoDetect.Visibility.ANY);

JSON object:

public class LogInUser {
    public String identifier, password;
    public LogInUser() {}
}

Is this possible given my configuration?

Upvotes: 1

Views: 936

Answers (1)

HyperCell
HyperCell

Reputation: 60

You could try using JsonCreator within your LogInUser class as mentioned here. When introduced into the code you posed in your quesion, it would look something like this:

public class LogInUser {

    @JsonCreator
    public LogInUser(@JsonProperty(value = "identifier", required = true) String identifier, @JsonProperty(value = "password", required = true) String password) {
    this.identifier = identifier;
    this.password = password;
    }

    public String identifier, password;
    public LogInUser() {}

}

When one or more of the values are null, it should throw an exception.

Upvotes: 1

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