Reputation: 625
Very new, please be nice and explain slowly and clearly. Thanks :)
I've tried searching how to extract a single line in python, but all the responses seem much more complicated (and confusing) than what I'm looking for. I have a file, it has a lot of lines, I want to pull out just the line that starts with #.
My file.txt:
"##STUFF"
"##STUFF"
#DATA 01 02 03 04 05
More lines here
More lines here
More lines here
My attempt at a script:
file = open("file.txt", "r")
splitdata = []
for line in file:
if line.startswith['#'] = data
splitdata = data.split()
print splitdata
#expected output:
#splitdata = [#DATA, 1, 2, 3, 4, 5]
The error I get:
line.startswith['#'] = data
TypeError: 'builtin_function_or_method' object does not support item assignment
That seems to mean it doesn't like my "= data", but I'm not sure how to tell it that I want to take the line that starts with # and save it separately.
Upvotes: 1
Views: 4169
Reputation: 1245
That's an if condition that expects predicate statement not the assignment.
if line.startswith('#'):
startswith(...) S.startswith(prefix[, start[, end]]) -> bool
Return True if S starts with the specified prefix, False otherwise. With optional start, test S beginning at that position. With optional end, stop comparing S at that position. prefix can also be a tuple of strings to try.
Upvotes: 0
Reputation: 33764
Although you're relatively new, you should start learning to use list comprehension, here is an example on how you can use it for your situation. I explained the details in the comments and the comments are matched to the corresponding order.
splitdata = [line.split() for line in file if line.startswith('#')]
# defines splitdata as a list because comprehension is wrapped in []
# make a for loop to iterate through file
#checks if the line "startswith" a '#'
# note: you should call functions/methods using the () not []
# split the line at spaces if the if startment returns True
Upvotes: 1
Reputation: 2688
Correct the if statement and the indentation,
for line in file:
if line.startswith('#'):
print line
Upvotes: 4