Reputation: 43
I am trying to call some functions through asyncio. I was following http://www.giantflyingsaucer.com/blog/?p=5557 this tutorial. It doesn't talk about how to call other functions.
import asyncio
def print_myname():
return ("My name is xyz")
def print_myage():
return ("My age is 21")
@asyncio.coroutine
def my_coroutine(future, task_name, function_call):
print("Task name", task_name)
data = yield from function_call
#yield from asyncio.get_function_source(function_call) #I was trying this too
future.set_result(data)
def got_result(future):
return future.result()
loop = asyncio.get_event_loop()
future1 = asyncio.Future()
future2 = asyncio.Future()
tasks = [
my_coroutine(future1, 'name', print_myname()),
my_coroutine(future2, 'age', print_myage())]
name = future1.add_done_callback(got_result)
age = future2.add_done_callback(got_result)
loop.run_until_complete(asyncio.wait(tasks))
loop.close()
print ("name output", name)
print ("age output", age)
It throws a runtime error that it is not able to yield.
Task exception was never retrieved
future: <Task finished coro=<my_coroutine() done, defined at /home/user/Desktop/testproject/source//weather/async_t.py:11> exception=RuntimeError("Task got bad yield: 'M'",)>
Traceback (most recent call last):
result = coro.throw(exc)
File "/home/user/Desktop/testproject/source/weather/async_t.py", line 14, in my_coroutine
data = yield from function_call
RuntimeError: Task got bad yield: 'M'
Through the exception it seems that it has gone to the function, but unable to execute the code.
Upvotes: 0
Views: 2281
Reputation: 30472
To call a regular function, just call it. You can not yield from
a regular function - just from a coroutine.
Instead of:
data = yield from foo()
Just use:
data = foo()
Upvotes: 1