CODEWITHSUNDEEP
c#.netarraysinitializationbitarray
nrocha
nrocha

Reputation: 394

Array of fixed-length BitArrays

I'm in trouble with a BitArray.

The goal is to simulate a stack of 8 80bit BitArrays, numbered from 0 to 7.

I just need to be able to access them by index, and so I think a simple array will be enough for me.

When initialising a BitArray object, I need to specify the number of bits it will contain, which gives me

BitArray test = new BitArray(80);

How can I do an Array of it, knowing I need to specify the length value?

I've tried several things, like 

BitArray[] stack = new BitArray(80)[];

but I always get an error when trying to give it the length...

Any thoughts?

Thanks in advance

Upvotes: 3

Views: 1800

Answers (3)

nrocha
nrocha

Reputation: 394

Well...

I finally did it this way:

List<BitArray> stack = new List<BitArray>(8);

public FPU()
{
    //initialise the stack

    for (int i = 0; i < stack.Capacity; i++)
    {
        stack[i] = new BitArray(80);
    }
}

Thanks for your answers, which leaded me to this solution, wich seems to work for me.

Have a nice day, and again, thanks!

Upvotes: -1

riffnl
riffnl

Reputation: 3183

First create your BitArray array ([]) like this: 

BitArray[] stack = new BitArray[8];

and then initialize all seperate bitarrays in a for-loop (something like this):

foreach (BitArray arr in stack)
{
    arr = new BitArray(80);
}

Edit: the something like this was more or less a pointer, not actually tested; this below is:

BitArray[] stack = new BitArray[8];
for(int i=0;i<stack.Length;i++)
{
    stack[i] = new BitArray(80);
}
stack[0][0] = true;

Upvotes: 2

Ani
Ani

Reputation: 113402

Unfortunately, the framework doesn't appear to have a "canonical" array-initialization pattern, as far as I know.

One way, using LINQ, would be:

var stack = Enumerable.Range(0, 8)
                      .Select(i => new BitArray(80))
                      .ToArray();

or:

var stack = Enumerable.Repeat<Func<BitArray>>( () => new BitArray(80), 8)
                      .Select(f => f())
                      .ToArray();

Alternatively, 

BitArray[] stack = new BitArray[8];

for(int i = 0; i < stack.Length; i++)
   stack[i] = new BitArray(80);

Upvotes: 4

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