CODEWITHSUNDEEP
pythondatetime
kieran
kieran

Reputation: 2312

python count down to event (in days and hours)

Please can someone advise on this, I've tried various methods but don't seem to be able to get it to work.

I just need a countdown from

datetime.now()

to 

datetime(2011,05,05)

in days hours

Upvotes: 4

Views: 19550

Answers (3)

Sven Marnach
Sven Marnach

Reputation: 601401

You can use

delta = datetime.datetime(2011, 5, 5) - datetime.datetime.now()

to get a datetime.timedelta object describing the remaining time. The number of remaining days is delta.days, the remaining hours delta.seconds/3600. or delta.seconds//3600.

Upvotes: 12

aeter
aeter

Reputation: 12700

>>> days_till_doomsday = \
...   (datetime.datetime(2011,05,05) - datetime.datetime.now()).days
>>> days_till_doomsday
154
>>> hours_till_midnight_today = 24 - datetime.datetime.now().hour
>>> hours_till_midnight_today
5
>>> hours_till_doomsday = \
...   (days_till_doomsday * 24) + hours_till_midnight_today
>>> hours_till_doomsday
3701

Does this help?

Upvotes: 0

Srikar Appalaraju
Srikar Appalaraju

Reputation: 73588

You could try this - 

import datetime

dt  = datetime.datetime
now = dt.now()

# This gives timedelta in days
dt(year=2011,month=05,day=05) - dt(year=now.year, month=now.month, day=now.day)

# This gives timedelta in days & seconds
dt(year=2011,month=05,day=05) - dt(year=now.year, month=now.month, day=now.day, minute=now.minute)

Upvotes: 0

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