CODEWITHSUNDEEP
linuxbashshellscripting
Pramod
Pramod

Reputation: 848

linux dialog --checklist error

I am working on following linux dialog box. I am not able to understand it's behavior. This works correctly i.e. correctly displays three checkboxes.

#!/bin/sh

dialog --backtitle "Test" \
--title "Checkbox test " \
--checklist "Choose from following"  0 0 0 \
apple "The apple is green" on \
mango "The mango is golden" on \
pappaya "The pappaya is brown" on \
2> /tmp/optional.out
OPTIONAL=`cat /tmp/optional.out | \
    sed -e "s/\"//g" -e "s/ /|/g" -e "s/|$//"`
    echo 'optional :'$OPTIONAL

After execution i get following output as. optional :apple|mango|pappaya

However I want to show the user only two options. So I made the following changes. 

#!/bin/sh

dialog --backtitle "Test" \
--title "Checkbox test " \
--checklist "Choose from following"  0 0 0 \
apple "The apple is green" on \
mango "The mango is golden" on \
#pappaya "The pappaya is brown" on \
2> /tmp/optional.out
OPTIONAL=`cat /tmp/optional.out | \
    sed -e "s/\"//g" -e "s/ /|/g" -e "s/|$//"`
    echo 'optional :'$OPTIONAL

But after doing this I get no output i.e. optional :. Why is that? How can I make it work.

Upvotes: 0

Views: 1041

Answers (1)

J. Chomel
J. Chomel

Reputation: 8395

I'm now thinking you did comment and broke your line. (it happens many times to me)

You may try this:

#!/bin/sh

dialog --backtitle "Test" \
--title "Checkbox test " \
--checklist "Choose from following"  0 0 0 \
apple "The apple is green" on \
mango "The mango is golden" on \
2> /var/tmp/optional.out
OPTIONAL=`cat /var/tmp/optional.out | \
    sed -e "s/\"//g" -e "s/ /|/g" -e "s/|$//"`
    echo 'optional :'$OPTIONAL

Upvotes: 1

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