Reputation: 3
I have web service written in Liferay. I want to get data in Java Client that is running on a separate machine.how can i do this? I have tried this but i am getting following error
{"message":"Authenticated access required","exception":"java.lang.SecurityException"}
My Code is below
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
public class JavaClient {
// http://localhost:8080/RESTfulExample/json/product/get
public static void main(String[] args)
{
try
{
// URL url = new
// URL("http://localhost:8080/api/jsonws/us-pharmacy-ui-portlet.ph_fax/get-documents-to-fax
// \-u [email protected]:test");
HttpURLConnection conn = (HttpURLConnection) getURL().openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Accept", "application/json");
if(conn.getResponseCode() != 200){ throw new RuntimeException("Failed : HTTP error code : " + conn.getResponseCode()); }
BufferedReader br = new BufferedReader(new InputStreamReader((conn.getInputStream())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null)
{
System.out.println(output);
}
conn.disconnect();
}
catch (MalformedURLException e)
{
e.printStackTrace();
}
catch (IOException e)
{
e.printStackTrace();
}
}
private static URL getURL() throws MalformedURLException
{
String url = "http://localhost:8080";
String screenName = "shahid.rana";
String password = "123";
int pos = url.indexOf("://");
String protocol = url.substring(0, pos + 3);
String host = url.substring(pos + 3, url.length());
StringBuilder sb = new StringBuilder();
sb.append(protocol);
sb.append(screenName);
sb.append(":");
sb.append(password);
sb.append("@");
sb.append(host);
sb.append("/api/jsonws/us-pharmacy-ui-portlet.ph_fax/get-documents-to-fax/");
// sb.append(serviceName);
System.out.println("sb.toString()" + sb.toString());
return new URL(sb.toString());
}
}
Upvotes: 0
Views: 741
Reputation: 6949
Yes, you will get this error because Liferay Web services needs basic Auth. you need to set [email protected] & whatever-password in base64 & pass it along.
Example code using HttpClient
HttpHost targetHost = new HttpHost("localhost", 8080, "http");
DefaultHttpClient httpclient = new DefaultHttpClient();
BasicHttpContext ctx = new BasicHttpContext();
// Plugin Context Use for Liferay 6.1
HttpPost post = new HttpPost("/api/jsonws/country/get-countries");
Base64 b = new Base64();
String encoding = b.encodeAsString(new String("[email protected]:test").getBytes());
post.setHeader("Authorization", "Basic " + encoding);
List<NameValuePair> params = new ArrayList<NameValuePair>();
//params.add(new BasicNameValuePair("emplyeeId", "30722"));
UrlEncodedFormEntity entity = new UrlEncodedFormEntity(params, "UTF-8");
post.setEntity(entity);
HttpResponse resp = httpclient.execute(targetHost, post, ctx);
resp.getEntity().writeTo(System.out);
httpclient.getConnectionManager().shutdown();
}
Please note
String encoding = b.encodeAsString(new String("[email protected]:test").getBytes());
post.setHeader("Authorization", "Basic " + encoding);
Upvotes: 1