CODEWITHSUNDEEP
bashshellunix
knkarthick24
knkarthick24

Reputation: 3216

Remove Files of given range in bash/shell/unix

I have files of below name format. 

test_1_452161_987654321.ARC  
test_1_452162_987654321.ARC  
test_1_452163_987654321.ARC  
.  
.  
.  
test_1_452190_987654321.ARC

i.e i need to delete 30 files in the above case where user will give the below inputs

Start_File = 452161  
End_File   =  452190

How to delete the above series files? (i am new to bash/shell programming i tried using while loop and remove which dint work so seeking experts help)

My Code

echo "Enter Start File"
read start
echo "Enter End File"
read end

i=$start
j=$end

while [$i -le $j]; do
rm *$i*.ARC
((i++))
done

Upvotes: 0

Views: 287

Answers (4)

mhawke
mhawke

Reputation: 87074

Just to add to your options, you can use seq:

echo "Enter Start File"
read start
echo "Enter End File"
read end

for i in $(seq $start $end)
do
    rm -f *_${i}_*.ARC
done

To me this seems clean and clear.

Upvotes: 0

JarrodCTaylor
JarrodCTaylor

Reputation: 9

You may be interested in expanding a sequence additional documentation. The code below will echo the file names you are interested in based on the provided start and end input. 

echo -n "Enter Start File => "; read start
echo -n "Enter End File => "; read end

for file in *{$start..$end}*
do
    echo $file
done

EDIT: Variable expansion works in zsh but not bash

Upvotes: 0

Cyrus
Cyrus

Reputation: 88583

Replace everything after fourth line by

for ((i=$start; i<=$end; i++)); do
  echo rm *_${i}_*.ARC
done

If everything looks fine, remove echo.

Upvotes: 1

anubhava
anubhava

Reputation: 785128

You can use awk + xargs:

printf "%s\n" test*ARC | awk -v s=452161 -v e=452190 -F_ '$3 >= s && $3 <= e' | xargs rm

awk is splitting file names on _ and then checking 3rd field is within start/end range.

Upvotes: 1

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