CODEWITHSUNDEEP
linuxbashawksed
berlloon
berlloon

Reputation: 41

Remove the path prefix of the fullpath stored in a file

I have a file containing multiple full path

/home/pi/1.txt
/home/pi/2.txt
/home/pi/3.txt

and I want to get the basename of every file

1.txt
2.txt
3.txt

I only know that I can get the every line and use command 

basename

Is it possible to achive my goal more simple? Thank you.

Upvotes: 0

Views: 399

Answers (4)

James Brown
James Brown

Reputation: 37404

Another in awk:

$ awk 'sub(/.*\//,"")||1' file
1.txt
2.txt
3.txt

Upvotes: 2

RavinderSingh13
RavinderSingh13

Reputation: 133458

@try:

awk -F"/" '{print $NF}'   Input_file

Making "/" as field separator and printing the last field of each line.

Upvotes: 1

user8017719
user8017719

Reputation:

A solution that use only shell tools:

readarray -t arr <file.txt
echo "${arr[@]##*/}"

This assumes that each file is one line (even with spaces). Filenames with newlines will fail as some other structure would be needed in the file.

Upvotes: 1

Olli K
Olli K

Reputation: 1760

The simplest way I came up with is this:

 basename -a $(<foo.txt)

Which works because the process substitution $() is the redirected output of the file, which is then split into multiple arguments because of word-splitting. Basename takes multiple args with -a.

Note that this doesn't work if there are spaces in the pathnames in the file (because of the said wordsplitting).

Upvotes: 2

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