CODEWITHSUNDEEP
scala
salvob
salvob

Reputation: 1370

Scala: List of Option tuples in a map

I have a List of values that could be None

val list = List(("apples",1), ("oranges",3), ("avocado",4), None, ("pears",10))

how can i transform this into a Map like :

Map("apples"->1, "oranges"->3, "avocado"->4, "pears"->10)

that skips the null elements?

I can't use a toMap to list because it gives me the error:

error: Cannot prove that Option[(String, Int)] <:< (T, U).

I was thinking of something like this:

val m = list.map(x => x match{case Some(x) => x._1->x._2 
case None => None})

but obviously I am missing something :(

Upvotes: 0

Views: 1113

Answers (2)

V-Lamp
V-Lamp

Reputation: 1678

You can do .flatten on the list to get only the non-None elements, the do a .toMap:

list  // : List[Option[(String,Int)]]
  .flatten // : List[(String,Int)]
  .toMap //: Map[String, Int]

Upvotes: 1

Nyavro
Nyavro

Reputation: 8866

Try this:

list.collect{case (k,v) => (k,v)}.toMap

Upvotes: 3

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