Reputation: 133
I can't understand how print
works, I didn't find good information.
declare @count int,
@experience varchar(30),
@date date,
@salary_old int,
@salary_new int,
@first_name varchar(30),
@second_name varchar(30),
@last_name varchar(30),
@i int=0
set @count = (select count(*) from cadre)
print ('-----------------------------------------------------------------------------------\n')
print ('id\tfirst_name\tsecond_name\tlast_name\told_salary\tnew_salary\texperience(years)\n')
WHILE @i < @count
BEGIN
set @date = (select date_of_start_work from cadre where id_cadre=@i)
set @first_name = rtrim((select first_name from cadre where id_cadre=@i))
set @second_name = rtrim((select @second_name from cadre where id_cadre=@i))
set @last_name = rtrim((select @last_name from cadre where id_cadre=@i))
set @experience = rtrim(cast( ((select year( (SELECT GETDATE() ))) - (select year(@date))) as varchar(30) ))
set @salary_old = rtrim(cast((select salary from cadre where id_cadre=@i) as varchar(30)))
set @salary_new = @salary_old*(@experience/100+1);
update cadre
set salary = @salary_new
where id_cadre = @i
print(rtrim(cast(@i as varchar(10)))+'\t'+@first_name+'\t'+@second_name+'\t'+@last_name+'\t'+@salary_old+'\t'+rtrim(cast(@salary_new as varchar(10)))+'\t'+@experience+N'\t')
set @i=@i+1
END
print(@count)
ERROR:
Msg 245, Level 16, State 1, Line 28
Ошибка преобразования значения varchar "\t" в тип данных int.Error converting varchar "\ t" value to data type int.
Upvotes: 0
Views: 43