CODEWITHSUNDEEP
c++arraysfunctionmemorydynamic
MJ1986
MJ1986

Reputation: 47

Passing a Dynamically Created Array as an Argument

Can someone help me figure out how to pass a dynamically created array as function argument.

I've created a 2D dynamic array as follows:

//matrix rows and columns
int rows=0;
int cols=0; 


int** matrix = new int*[rows]; 

//creates the matrix
for (int i =0; i < rows; ++i)
    matrix[i] = new int[cols];

I'd like to pass this array into a function with a prototype like this:

void readMatrix(int **matrix[], int size);

I can't figure out how to do this! I don't know what the argument should look like, I've tried many different ways and none work. Getting errors that say "expecting expression" or "argument doesn't match parameter"

Upvotes: 0

Views: 81

Answers (1)

YePhIcK
YePhIcK

Reputation: 5856

The function specifies the int **matrix[] for the type, which is equivalent to a type int ***matrix. So what you need is another indirection. Use &matrix as an argument.

Also, as mentioned in comments, re-think the whole idea of using the plain arrays in favor of a more modern std::vector<> one.

Upvotes: 2

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