CODEWITHSUNDEEP
pythonhtmlxpath
morea030
morea030

Reputation: 430

XPath for selecting all siblings until a div

I have the following HTML structure. Each <div> represents a state and each <a> tag represents a city within that state

<div class="country">AL</div>
<a href=somelink>City1</a>
<a href=somelink>City2</a>
<a href=somelink>City3</a>
<a href=somelink>City4</a>
<a href=somelink>City5</a>
<div class="country">CA</div>
<a href=somelink>City21</a>
<a href=somelink>City22</a>
<a href=somelink>City23</a>
<a href=somelink>City24</a>
<div class="country">IL</div>
<a href=somelink>City31</a>
<a href=somelink>City32</a>
<a href=somelink>City33</a>
<a href=somelink>City34</a>

I need to extract all a tags that belong to a certain state.
I tried this:

//*[contains(text(), "CA")]/following-sibling::a[preceding::div]

But it got me

City21 City22 City23 City24 City31 City32 City33 City34

while I only wanted

City21 City22 City23 City24

Upvotes: 1

Views: 348

Answers (2)

Andersson
Andersson

Reputation: 52685

Try below XPAth expression:

//a[count(following-sibling::div)=count(//div[text()="AL"]/following-sibling::div)-1]

or 

//a[preceding-sibling::div[2][text()="AL"]]

Upvotes: 4

splash58
splash58

Reputation: 26153

You can select tags a such that the first div before contains the state abbreviation:

//a[preceding::div[1][contains(text(), "CA")]]

Upvotes: 1

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