CODEWITHSUNDEEP
phpjquery
furkanali89
furkanali89

Reputation: 148

unserialize(): Error at offset 0 of 537 bytes

I am using this jQuery code to send data to PHP:

var fromdata2 = $('#form').serialize();
var file_data = $('#fileid').attr('files')[0];
var fromdata = new FormData();
fromdata.append('fileid', file_data);
fromdata.append('post_data', fromdata2);

$.ajax({
    type: "POST",
    cache: false,
    contentType: false,
    processData: false,
    data: fromdata,
    dataType: "json",
    url: "url",
    success: function (data)
    {
       alert("success");
    }
});

I receive the data in this form:

code=&id=&CTR_ID=&ctr_name=asdsadsad&air_name=Action+Airlines&air_uniCode=XQ&ctr_strDate=04%2F11%2F2017&ctr_endDate=04%2F11%2F2017&ctr_docNameHid=5337XXXXXXXXXX78_09-06-2016&recstatus_val=1

But when I attempt to process it, with this code:

var_dump(unserialize($data));

I receive this error:

unserialize(): Error at offset 0 of 537 bytes.

How can i unserialize it, to find the result in an array, like this:

array(
code=>,
id=>,
CTR_ID=>,
ctr_name=>'asdsadsad'
)

Upvotes: 0

Views: 1983

Answers (2)

Manish Jangir
Manish Jangir

Reputation: 5437

As said by @apokryfos in the comment, you can use parse_str to parse the query strings like below:

$queryString = "code=&id=&CTR_ID=&ctr_name=asdsadsad&air_name=Action+Airlines&air_uniCode=XQ&ctr_strDate=04%2F11%2F2017&ctr_endDate=04%2F11%2F2017&ctr_docNameHid=5337XXXXXXXXXX78_09-06-2016&recstatus_val=1";

parse_str($queryString, $queryArray);

print_r($queryArray);

To upload multiple files:

var ins = document.getElementById('fileid').files.length;
for (var x = 0; x < ins; x++) {
    fromdata.append("fileid[]", document.getElementById('fileid').files[x]);
}

Upvotes: 1

alpham8
alpham8

Reputation: 1362

You are trying to send JSON data but you give it form url-encoded data, which are two different things. If you want to send JSON just do something like this:

var form_data = $("#form").serializeArray()
form_data.push({fileid: $('#fileid').attr('files')[0]});

$.ajax({
    type: "POST",
    cache: false,
    contentType: false,
    processData: false,
    data: fromdata,
    dataType: "json",
    url: "url",
    success: function (data)
    {
       alert("success");
    }
});

And then on PHP side just do json_decode(file_get_contents('php://stdin'), true);

Upvotes: 0

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