CODEWITHSUNDEEP
swiftswift3
Chris G.
Chris G.

Reputation: 25964

String.CharacterView - how to convert to String

I have tried the following:

let str = self.passwordLabel.text?.characters.dropLast()
let s = String(describing: str)

But it give me the following:

"Optional(Swift.String.CharacterView(_core: Swift._StringCore(_baseAddress: Optional(0x0000618000051e10), _countAndFlags: 9223372036854775810, _owner: Optional(Swift._HeapBufferStorage<Swift._StringBufferIVars, Swift.UInt16>)), _coreOffset: 0))"

I just wanted to remove the last char from the string?

Upvotes: 3

Views: 1170

Answers (2)

vadian
vadian

Reputation: 285069

You need to unwrap the optional string and don't use the describing initializer.

if let passwordText = self.passwordLabel.text {
    let s = String(passwordText.characters.dropLast())
}

or if it's guaranteed that text is not nil

let s = String(self.passwordLabel.text!.characters.dropLast())

Upvotes: 3

shallowThought
shallowThought

Reputation: 19602

Do not use String(describing:...) and unwrap the optional str.

let passwordLabel = UILabel()
passwordLabel.text = "TEXT1"
if let str = passwordLabel.text?.characters.dropLast() {
    let s = String(str)
    print(s)
}

Prints: TEXT

Upvotes: 2

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