CODEWITHSUNDEEP
pythonpython-3.x
teatag
teatag

Reputation: 13

Creating a float in a list of objects

I have a list of objects,

l = (('a1', 1.96256684), ('b3', 1.36), ('e2', 0.5715))

I want to be able to format the numbers to a certain number of decimal places (4) in order to get an output like

a1 1.9626 b3 1.3600 e3 0.5715

I tried the method described here (using isalpha) but get the error

AttributeError: 'tuple' object has no attribute 'isalpha'

I'm wondering if it's because the alphabetic letters have numbers attached to them? But then I would think it would just return False instead of giving me an error.

Thank you for any help or adivce

Upvotes: 1

Views: 55

Answers (2)

wim
wim

Reputation: 362617

Print statement will join with spaces anyway, so you can unpack the args with a splat:

>>> print(*(f'{s} {f:.4f}' for s,f in l))
a1 1.9626 b3 1.3600 e2 0.5715

This uses the literal string interpolation feature, new in Python 3.6.

Upvotes: 2

mgilson
mgilson

Reputation: 309891

You probably want to format the strings using .format.

>>> '{:0.4f}'.format(1.36)
'1.3600'
>>> '{:0.4f}'.format(1.96256684)
'1.9626'

The full code could look something like:

' '.join('{} {:0.4f}'.format(*t) for t in l)

Upvotes: 2

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