CODEWITHSUNDEEP
phppreg-replacepreg-match
teoman_d
teoman_d

Reputation: 15

finding plus "+" character with number like +90 90+ in string

I tried so many preg_replace and preg_match codes but i cant do. I try to find strings contain +18 , 18+ or (+18) I cant explain but you can understand when see my codes. 

//inputs 
$product='example: 18 kg apple'; // my hope output: EVERYONE
$product='water pipe (18) meters'; // my hope output: EVERYONE
//outputs: OVER 18 

$product='product +18 dress';   // my hope output: OVER 18    
$product='product 18+ dress';   // my hope output: OVER 18
$product='product (+18) dress';     // my hope output: OVER 18
//outputs are already OVER 18 
//Because of contain 18 
//not +18 or 18+. it doesnt work truly


    preg_match('/\b(\w*18\w*)\b/', $product, $match);

        if( $match[1]=='+18' || $match[1]=='18+' ) { 

                echo "OVER 18<br>"; 
    }
       else{
               echo "EVERYONE<br>";

                }

Upvotes: 0

Views: 88

Answers (2)

Philipp
Philipp

Reputation: 15629

In this simple case, I wouldn't use an regex. Just using strpos would also do the job.

if (strpos($product, '18+') !== false || strpos($product, '+18') !== false) {
    // over 18
}

Upvotes: 0

junkfoodjunkie
junkfoodjunkie

Reputation: 3178

Use this: (\+18|18\+)- it checks if +18 or 18+ exists in the string.

So something like this: preg_match('(\+18|18\+)', $product, $match); should work.

Only tested it here https://regex101.com/ (a very good place to test regexp

Upvotes: 1

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