Reputation: 263
I have a function as below:
function foo(args1, args2, retry)
{
if (retry <= 0)
return false;
var isDone = callAnotherFunction(args1, args2);
if(!isDone) {
setInterval(function () {
foo(args1, args2, retry-1);
},
2000);
}
else
return true;
}
So I am not sure if the above implementation is correct. But I need to use this function in another function. And use the above function in an if block to decide if the other statement needs to be executed. Below is the usage of the above function.
function useIt(args1, args2)
{
// Other code
let store = function() {
if(!foo(args1, args2, 5)) {
cleanStorage(args1, args2);
return;
}
}
So the problem is in function useIt()
, cleanStorage()
does not wait for foo()
to be executed if I am using setInterval
or setTimeOut
. So how do I need to implement the function foo()
? Kindly help me.
Upvotes: 3
Views: 7751
Reputation: 9814
consider using promises
foo can be rewritten like this (I've replace setInterval
with setTimeout
):
function foo(args1, args2, retry) {
return new Promise(function (resolve, reject) {
if (retry <= 0)
reject();
var isDone = callAnotherFunction(args1, args2);
if (!isDone) {
setTimeout(function () {
resolve(foo(args1, args2, retry - 1));
}, 2000);
}
else
resolve(true);
})
}
and then use it like this:
function useIt(args1, args2) {
// Other code
let store = function () {
foo(args1, args2, 5).then(function () {
cleanStorage(args1, args2);
});
}
}
Upvotes: 7
Reputation: 3062
You should use Promises to do this
Something like this:
function foo(args1, args2, retry)
{
return new Promise(function(resolve, reject) {
if (retry <= 0)
reject();
var isDone = callAnotherFunction(args1, args2);
if(!isDone) {
setInterval(function () {
retry = retry - 1;
isDone = callAnotherFunction(args1, args2);
if (isDone)
resolve();
},
2000);
}
else
resolve();
}
}
function useIt(args1, args2)
{
// Other code
let store = function() {
foo(args1, args2, 5).then(result => {
cleanStorage(args1, args2);
return;
}
}
}
Upvotes: 6