CODEWITHSUNDEEP
javafunctional-programmingjava-8java-stream
Tuomas Toivonen
Tuomas Toivonen

Reputation: 23492

How to reduce list to map with Java functional API

I want to transform a string of text to a dictionary, which contains all the unique words as a key, and translation as a value.

I know how to transform a String into a stream containing unique words (Split -> List -> stream() -> distinct()), and I have translation service available, but what is the most convenient way to reduce the stream into Map with the original element and it's translation in general?

Upvotes: 9

Views: 9388

Answers (3)

freedev
freedev

Reputation: 30067

Suppose you have a list of strings "word1", "word2", "wordN" with no repetitions:

This should solve the the problem

List<String> list = Arrays.asList("word1", "word2", "workdN");
    
Map<String, String> collect = list.stream()
   .collect(Collectors.toMap(s -> s, s -> translationService(s)));

This will return, the insertion order is not maintained.

{wordN=translationN, word2=translation2, word1=translation1}

Upvotes: 5

shizhz
shizhz

Reputation: 12501

Try the following code:

public static void main(String[] args) {
    String text = "hello world java stream stream";

    Map<String, String> result = new HashSet<String>(Arrays.asList(text.split(" "))).stream().collect(Collectors.toMap(word -> word, word -> translate(word)));

    System.out.println(result);
}

private static String translate(String word) {
    return "T-" + word;
}

Will give you output:

{java=T-java, world=T-world, stream=T-stream, hello=T-hello}

Upvotes: 1

Gabe
Gabe

Reputation: 441

You can directly do that via collect:

yourDistinctStringStream
.collect(Collectors.toMap(
    Function.identity(), yourTranslatorService::translate
);

This returns a Map<String, String> where the map key is the original string and the map value would be the translation.

Upvotes: 12

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