CODEWITHSUNDEEP
python
Tony
Tony

Reputation: 2107

How do I turn this into a one line generator?

My best attempts have failed:

for s in self.services:
  for m in s.messages: yield m

Upvotes: 0

Views: 197

Answers (2)

Jochen Ritzel
Jochen Ritzel

Reputation: 107686

itertools.chain.from_iterable(s.messages for s in self.services)

Upvotes: 3

Karl Knechtel
Karl Knechtel

Reputation: 61635

(m for s in self.services for m in s.messages)

... as counter-intuitive as it seems.

Upvotes: 7

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