Bits tricks and magic

Question

I'm writing a program in C++, and it has to be as minimal as possible. I need some help with an if/else statement. This is the code:

if (lines & 1 << ((d & 1) * 30 + 5 * l + c)) {
    cout << "Invalid";
} else {
    lines |= 1 << ((d & 1) * 30 + 5 * l + c);
}

What i'm doing here is: verifing if a bit is set to 1 and I cout something, and if it's not, i'll set it to 1. Is there any way i can combine the 2 lines where i verify and where i set bit to 1 in the if body?

lines & 1 << ((d & 1) * 30 + 5 * l + c)
lines |= 1 << ((d & 1) * 30 + 5 * l + c)

I'm imagining something like:

if (lines |= .... )

And what it should do is: verify if bit is 1 and entering the if body, and if it's not(or it is already) make it 1.

Sorry for my poor english and this stupid request, but i can't figure out a way to do it and it drives me crazy.

P.S: Is there any site/calculator that can give me an boolean formula when i enter an equasion? ex: 3 .. .. = -1. and i need the operand and operator here.

Answer 1

if (lines == (lines|= mask)) cout << "Invalid";