Reputation: 66935
How to fill OpenCV image with one solid color?
Upvotes: 91
Views: 195112
Reputation: 1956
Here's how to do with cv2 in Python:
# Create a blank 300x300 black image
image = np.zeros((300, 300, 3), np.uint8)
# Fill image with red color(set each pixel to red)
image[:] = (0, 0, 255)
Here's more complete example how to create new blank image filled with a certain RGB color
import cv2
import numpy as np
def create_blank(width, height, rgb_color=(0, 0, 0)):
"""Create new image(numpy array) filled with certain color in RGB"""
# Create black blank image
image = np.zeros((height, width, 3), np.uint8)
# Since OpenCV uses BGR, convert the color first
color = tuple(reversed(rgb_color))
# Fill image with color
image[:] = color
return image
# Create new blank 300x300 red image
width, height = 300, 300
red = (255, 0, 0)
image = create_blank(width, height, rgb_color=red)
cv2.imwrite('red.jpg', image)
Upvotes: 45
Reputation: 370
color=(200, 100, 255) # sample of a color
img = np.full((100, 100, 3), color, np.uint8)
Upvotes: 8
Reputation: 104
I personally made this python code to change the color of a whole image opened or created with openCV . I am sorry if it's not good enough , I am beginner 😚😚 .
def OpenCvImgColorChanger(img,blue = 0,green = 0,red = 0):
line = 1
ImgColumn = int(img.shape[0])-2
ImgRaw = int(img.shape[1])-2
for j in range(ImgColumn):
for i in range(ImgRaw):
if i == ImgRaw-1:
line +=1
img[line][i][2] = int(red)
img[line][i][1] = int(green)
img[line][i][0] = int(blue)
Upvotes: 0
Reputation: 9961
Use numpy.full
. Here's a Python that creates a gray, blue, green and red image and shows in a 2x2 grid.
import cv2
import numpy as np
gray_img = np.full((100, 100, 3), 127, np.uint8)
blue_img = np.full((100, 100, 3), 0, np.uint8)
green_img = np.full((100, 100, 3), 0, np.uint8)
red_img = np.full((100, 100, 3), 0, np.uint8)
full_layer = np.full((100, 100), 255, np.uint8)
# OpenCV goes in blue, green, red order
blue_img[:, :, 0] = full_layer
green_img[:, :, 1] = full_layer
red_img[:, :, 2] = full_layer
cv2.imshow('2x2_grid', np.vstack([
np.hstack([gray_img, blue_img]),
np.hstack([green_img, red_img])
]))
cv2.waitKey(0)
cv2.destroyWindow('2x2_grid')
Upvotes: 9
Reputation: 20340
Create a new 640x480 image and fill it with purple (red+blue):
cv::Mat mat(480, 640, CV_8UC3, cv::Scalar(255,0,255));
Note:
Upvotes: 14
Reputation: 2321
If you are using Java for OpenCV, then you can use the following code.
Mat img = src.clone(); //Clone from the original image
img.setTo(new Scalar(255,255,255)); //This sets the whole image to white, it is R,G,B value
Upvotes: 4
Reputation: 17265
Using the OpenCV C API with IplImage* img
:
Use cvSet(): cvSet(img, CV_RGB(redVal,greenVal,blueVal));
Using the OpenCV C++ API with cv::Mat img
, then use either:
cv::Mat::operator=(const Scalar& s)
as in:
img = cv::Scalar(redVal,greenVal,blueVal);
or the more general, mask supporting, cv::Mat::setTo()
:
img.setTo(cv::Scalar(redVal,greenVal,blueVal));
Upvotes: 114
Reputation: 6597
For an 8-bit (CV_8U) OpenCV image, the syntax is:
Mat img(Mat(nHeight, nWidth, CV_8U);
img = cv::Scalar(50); // or the desired uint8_t value from 0-255
Upvotes: 6
Reputation: 12514
The simplest is using the OpenCV Mat class:
img=cv::Scalar(blue_value, green_value, red_value);
where img
was defined as a cv::Mat
.
Upvotes: 11